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📅 March 10, 2026 👤 scraface

Mar 10, 2026

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Alternatively, use:
ho = c \sin\phi \Rightarrow
ho^2 = c^2 \sin^2\phi
But \(
ho^2 = x^2 + y^2 + z^2\), and \(\sin^2\phi = 1 - \cos^2\phi = 1 - rac...
ho^2}\)
x^2 + y^2 = c^2 \sin^4\phi, \quad z = c \sin\phi \cos\phi
Let \(r = \sqrt{x^2 + y^2} = c \sin^2\phi\)
But from \(z = c \sin\phi \cos\phi = c \sin\phi \sqrt{1 - \sin^2\phi}\...
Set \(u = \sin\phi\), then:

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