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Home » Here, \( a = 2 \), \( b = -3 \), and \( c = -5 \). - Tacotoon

Here, \( a = 2 \), \( b = -3 \), and \( c = -5 \). - Tacotoon

📅 March 9, 2026 👤 scraface

Mar 09, 2026

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📌 First compute \( lpha^2 \):

📌 lpha = 1 + i \Rightarrow lpha^2 = (1+i)^2 = 1 + 2i + i^2 = 1 + 2i - 1 = 2i

📌 lpha^4 = (lpha^2)^2 = (2i)^2 = 4i^2 = -4

📌 lpha^4 + 3 = -4 + 3 = -1 = a(1+i) + b = a + ai + b

📌 Equating real and imaginary parts:

📌 Real: \( a + b = -1 \)

📌 Imaginary: \( a = 0 \)

📌 Wait â imaginary part gives \( a = 0 \)? But then from real: \( b = -1 \), so remainder is \( -1 \)? Letâs verify with the other root.

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