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Home » Men in Black 2 Cast Explosively Revealed—Who Was *Really* Along for the Ride? - Tacotoon

Men in Black 2 Cast Explosively Revealed—Who Was Really Along for the Ride? - Tacotoon

📅 March 10, 2026 👤 scraface

Mar 10, 2026

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📌 \mathbf{v} imes \mathbf{a} = a(-4) - b(3) = -4a - 3b

📌 We set this equal to 5:

📌 -4a - 3b = 5

📌 This is a linear equation in two variables. We can express one variable in terms of the other. Solving for \(b\):

📌 -3b = 4a + 5 \quad \Rightarrow \quad b = -rac{4a + 5}{3}

📌 Thus, all vectors \(egin{bmatrix} a \ -rac{4a + 5}{3} \end{bmatrix}\) satisfy the condition.

📌 To write a specific solution, choose \(a = -1\):

📌 b = -rac{4(-1) + 5}{3} = -rac{-4 + 5}{3} = -rac{1}{3}

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\int_0^1 \int_0^{\min(0.2, 1 - u)} 30 s^4 \, ds \, du
Split into two regions: $ 0 \leq u \leq 0.8 $, where $ 1 - u \geq 0.2...
= \int_0^{0.8} \int_0^{0.2} 30 s^4 ds \, du + \int_{0.8}^1 \int_0^{1 -...
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\int_0^{0.2} 30 \cdot \frac{s^5}{5} ds = 6 \int_0^{0.2} s^5 ds = 6 \cd...
Multiply by 1 (no outer u): $ \frac{1}{15625} $
Second integral:
\int_{0.8}^1 30 \cdot \frac{(1 - u)^5}{5} du = 6 \int_{0.8}^1 (1 - u)^...
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