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A) True, by definition — correct.
Because in any triangle, the area is $ A = r \cdot s $, where $ s $ is semiperimeter and $ r $ is inradius. This holds for right triangles as well.
Pregunta: In a right triangle with inradius $ r $ and semiperimeter $ s $, what is the relationship between the triangle’s area and $ r \cdot s $?

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